Purchase Oracle : 1Z0-007 Exam Materials and then pass exam easily

Updated: Oct 20, 2026

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Oracle 1Z0-007 Exam Overview:

Certification Vendor:Oracle
Exam Name:Introduction to Oracle9i: SQL
Exam Number:1Z0-007
Real Exam Qty:57
Exam Duration:120 minutes
Certificate Validity Period:Retired; perpetual validity if achieved before discontinuation
Available Languages:Spanish, English, Japanese
Related Certifications:Oracle9i DBA OCP
Oracle9i DBA OCA
Passing Score:70% (40 out of 57)
Exam Price:Approx. $195–$225 USD (historical, varies by region)
Exam Format:Multiple Select, Multiple Choice
Recommended Training:Oracle9i SQL Study Guide
Oracle University - Introduction to Oracle9i: SQL
Exam Registration:Oracle University (legacy)
Pearson VUE (historical)
Sample Questions:Oracle 1Z0-007 Sample Questions
Exam Way:In-person at Pearson VUE / Oracle Testing Centers (retired, no longer available)
Pre Condition:None required; recommended basic relational database knowledge
Official Syllabus URL:https://education.oracle.com/

Oracle 1Z0-007 Exam Syllabus Topics:

SectionWeightObjectives
Topic 1: Displaying Data from Multiple Tables15%- ANSI/ISO SQL99 joins
- Equijoins and non-equijoins
- Outer joins and self-joins
Topic 2: Creating and Managing Tables9%- CREATE, ALTER, DROP, RENAME tables
- Managing indexes, sequences, synonyms, views
- Data types and constraints
Topic 3: Writing Basic SQL SELECT Statements15%- Executing basic SELECT statements
- SQL vs iSQL*Plus commands
- Capabilities of SQL SELECT statements
Topic 4: Manipulating Data8%- Transaction control (COMMIT, ROLLBACK, SAVEPOINT)
- INSERT, UPDATE, DELETE statements
Topic 5: Restricting and Sorting Data12%- Limiting rows with WHERE clause
- Sorting results with ORDER BY
- Using substitution variables
Topic 6: Subqueries10%- Single-row and multi-row subqueries
- Using IN, ANY, ALL operators
Topic 7: Aggregating Data Using Group Functions13%- Filtering groups with HAVING
- GROUP BY clause
- Using COUNT, SUM, AVG, MAX, MIN
Topic 8: Single-Row Functions18%- Character, number, and date functions
- Conversion functions (TO_CHAR, TO_NUMBER, TO_DATE)
- Conditional expressions (NVL, DECODE)

Oracle Introduction to Oracle9i: SQL Sample Questions:

Question #1

Examine the structure of the EMPLOYEES and DEPARTMENTS tables:

You want to create a report displaying employee last names, department names, and locations. Which query should you use to create an equi-join?

  • A. SELECT employees.last_name, departments.department_name,
    departments.location_id
    FROM employees e, departments D
    WHERE e.department_id =d.department_id;
  • B. SELECT e.last_name, d.department_name, d.location_id
    FROM employees e, departments D
    WHERE manager_id =manager_id;
  • C. SELECT last_name, department_name, location_id
    FROM employees , departments ;
  • D. SELECT e.last_name, d.department_name, d.location_id
    FROM employees e, departments D
    WHERE e.department_id =d.department_id;
Reveal Solution  Discussion  0

Correct Answer: D  🗳️

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Question #2

Examine these statements:
CREATE ROLE registrar;
GRANT UPDATE ON student_grades TO registrar;
GRANT registrar to user1, user2, user3;
What does this set of SQL statements do?

  • A. The set of statements contains an error and does not work.
  • B. It creates a role called REGISTRAR, adds the MODIFY privilege on the STUDENT_GRADES object to the role, and gives the REGISTRAR role to three users.
  • C. It creates a role called REGISTRAR, adds the UPDATE privilege on three users, and gives the REGISTRAR role to the STUDENT_GRADES object.
  • D. It creates a role called REGISTRAR, adds the UPDATE privilege on the STUDENT_GRADES object to the role, and creates three users with the role.
  • E. It creates a role called STUDENT_GRADES, adds the UPDATE privilege on three users, and gives the UPDATE role to the registrar.
  • F. It creates a role called REGISTRAR, adds the UPDATE privilege on the STUDENT_GRADES object to the role, and gives the REGISTRAR role to three users.
Reveal Solution  Discussion  0

Correct Answer: F  🗳️

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Question #3

You need to write a SQL statement that returns employee name, salary, department ID, and maximum salary earned in the department of the employee for all employees who earn less than the maximum salary in their department.
Which statement accomplishes this task?

  • A. SELECT a.emp_name, a.sal, b.dept_id, MAX(sal) FROM employees a, departments b WHERE a.dept_id = b.dept_id AND a.sal < MAX(sal) GROUP BY b.dept_id;
  • B. SELECT emp_name, sal, dept_id, maxsal FROM employees, (SELECT dept_id, MAX(sal) maxsal FROM employees GROUP BY dept_id) WHERE a.sal < maxsal;
  • C. SELECT a.emp_name, a.sal, a.dept_id, b.maxsal FROM employees a WHERE a.sal < (SELECT MAX(sal) maxsal FROM employees b GROUP BY dept_id);
  • D. SELECT a.emp_name, a.sal, a.dept_id, b.maxsal FROM employees a, (SELECT dept_id, MAX(sal) maxsal FROM employees GROUP BY dept_id) b WHERE a.dept_id = b.dept_id AND a.sal < b.maxsal;
Reveal Solution  Discussion  0

Correct Answer: D  🗳️

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Question #4

Examine the data in the EMPLOYEES and DEPARTMENTS tables.

You want to retrieve all employees, whether or not they have matching departments in the departments table. Which query would you use?

  • A. SELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);
  • B. SELECT last_name, department_name FROM employees , departments(+);
  • C. SELECT last_name, department_name FROM employees JOIN departments (+);
  • D. SELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);
  • E. SELECT last_name, department_name FROM employees(+) e JOIN departments d ON (e.department_id = d.department_id);
  • F. SELECT last_name, department_name FROM employees(+) , departments ON (e.department_id = d.department_id);
Reveal Solution  Discussion  0

Correct Answer: A  🗳️

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Question #5

The STUDENT_GRADES table has these columns:
STUDENT_ID NUMBER (12)
SEMESTER_END DATE
GPA NUMBER (4,3)
The register has requested a report listing the students' grade point averages (GPA), sorted from highest grade point average to lowest within each semester, starting from the earliest date. Which statement accomplishes this?

  • A. SELECT student_id, semester_end, gpa FROM student_grades ORDER BY gpa DESC, semester_end DESC;
  • B. SELECT student_id, semester_end, gpa FROM student_grades ORDER BY semester_end DESC, gpa DESC;
  • C. SELECT student_id, semester_end, gpa FROM student_grades ORDER BY gpa DESC, semester_end ASC;
  • D. SELECT student_id, semester_end, gpa FROM student_grades ORDER BY semester_end, gpa DESC;
  • E. SELECT student_id, semester_end, gpa FROM student_grades ORDER BY semester_end ASC, gpa ASC;
Reveal Solution  Discussion  0

Correct Answer: D  🗳️

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